Others in Carbon monoxide topic said thats an awful proportion tho
Posting the math for the reaction again, since it gets buried under the newer posts.
This is the equation, already balanced:
CH2O2 + H2SO4 = CO + H2SO4.H2O
1 mole of formic acid + 1 mole of sulfuric acid = 1 mole of carbon monoxide + 1 mole hydrated sulfuric acid
CH2O2
molecular weight =46,03 grs/mol
density = 1,22 grs/cm3
H2SO4
molecular weight = 98,079 grs/mol
density = 1,8356 grs/cm3
CO
molecular weight = 28,01 grs/mol
density = 0,00125 grs/cm3
We don't care about the H2SO4.H2O!
The GULPS method consists of using 50 ml (50 cm3) of formic acid and 250 ml (250 cm3) of sulfuric acid. I was curious, how much CO does it really produce? (Keep in mind that without heat or agitation the reaction my not be complete)
50 ml/cm3 of CH2O2 weight 61 grs (1,22 grs x 50), which is 1,325 mole (61 grs / 46,03)
250 ml/cm3 of H2SO4 weight 458,9 grs (1,8356 grs x 250), which is 4,679 mole
This means we have an excess of sulfuric acid. About 1/3 would be enough to react with all the formic acid, but I guess this is to make sure there's enough and then some more.
How much CO does it produce then? The formic acid is therefore the limitation, from 1 mole of CH2O2 we get 1 mole of CO. From 50 ml, which are 1,325 moles, we'll get the same 1,325 moles of CO (if all the formic acid reacts, which may not happen due to the conditions in which the reaction happens). And how much is that? 1,325 moles of CO are 37,113 grs (1,325 x 28,01 grs) or 29690,4 cm3 (37,113 grs / 0,00125). That's
29,69 liters!!!
From 250 ml + 50 ml you can get 29,69 liters of CO!
But since, in my case, my formic is at 85%, then from 50 ml I'll get about 25 L of CO. Still impressive!
Just to take it one step further, considering we want at least 10000 ppm, meaning 1% of CO in the air, the amount of CO produced is enough for 2500 liters of air or 2,5 m3! So, theoretically, you don't even need a mask, you could let the reaction happen inside a small car and quickly get in and it'd most likely still work.