Method CHARCOAL CO METHOD. FULL RUN THROUGH OF THE LOGISTICS, WITH CALCULATIONS.

[knion]

1)introduction

2)what does each concentration of carbon monoxide do to me? Which concentration will kill me and how long will it take?

3)How much charcoal is enough?

4)How much space do I need?

5)I GUESS THE MOST IMPORTANT PART, FULL CALCULATIONS.

6)CONCLUSION

7)FINAL CONCLUSION



1)introduction


Hello everyone.

So, I posted yesterday about my attempt to end my life in august using the CO method.

And this morning I was thinking, you know what, f**k it, why not do some real calculations and research into this, rather than just making assumptions.


I made my attempt based on some advice on this website (which, btw was great advice l, because it gave me a general idea about how to go about trying to CTB in this way), But here and now, I hope, is a post with specific details about what needs to be done to CTB SuccessFully through the CO method.




And, as I've said a few times, just to cover myself legally, I do not think you should use this method to end your life, I DO NOT condone the use of this information to end your life and I am not coercing or encouraging you to end your life. Please use this information as an educational tool.




That being said, when I am to end my life, this is the method I will be using.




2)How much Carbon Monoxide does it take to get certain effects?


So, this section isn't a particularly academic, or well sourced one. I got this Information from Wikipedia.

But hey, I don't think we have much reason to not have faith in this information, it looks pretty sound, especially when compared to the paper I reference from later in this post.


Obviously, the higher the concentration of Carbon monoxide, the greater the effects.


Here are the concentrations and effects as listed by Wikipedia.

1,600 ppm (0.16%), (1.6‰)

Headache, increased heart rate, dizziness, and nausea within 20 min; death in less than 2 hour

3,200 ppm (0.32%), (3.2‰)

Headache, dizziness and nausea in five to ten minutes. Death within 30 mins.

6,400 ppm (0.64%), (6.4‰)

Headache and dizziness in one to two minutes. Convulsions, respiratory arrest, and death in less than 20 minutes

12,800 ppm (1.28%), (12.8‰)

Unconsciousness after 2–3 breaths. Death in less than three minutes

Just for a frame of reference:

5,000 ppm

Exhaust from a home wood fire

Obviously, 12,800 ppm seems almost impossible to achieve. The number looks huge in comparison to the measly 1,600 and to be honest it even trumps the 6,400 in double the size. (And to be honest, we have good reason to think this).

However, I am going to explain in the rest of this post how achieve-able each of these concentrations are… at least when we're talking about charcoal.




3)Charcoal and it's carbon monoxide output.


Don't worry!

In this section I will not be giving a chemistry or physics lesson in "how charcoal combusts and what it gives out" I feel that that would be a little unnecessary.

However, I will be discussing, based on a study I found online, how the amount of carbon monoxide relates to the concentration of CO in any given space.


Incase anybody wants to take a look, the website I will be referencing in this section is: https://www.bfr.bund.de/en/press_in...definitely_not_an_indoor_pursuit_-187998.html


So, without further ado (you can skip the quotes if you wish, I have summarised underneath):


"Owing to its spatial volume of 19 cubic metres, the cloud chamber provides a good model for a small garage or a living room. In the experiments, the CO concentration was measured both under the ceiling and in the immediate vicinity of the grill. No significant differences were detected, for the combustion gas was distributed relatively evenly throughout the room."


"After as little as two hours of glowing embers from 800 grams of charcoal, CO concentrations in excess of 3000 ppm (parts per million) were measured. If humans inhale ambient air of such concentrations, they faint after a few minutes"




So, as we can see here. In a 19 cubic metre space (which is a good example of a garage or living room), 800 grams of charcoal made a CO concentration more than 3000ppm in less than 2 hours.


Following this, the website tells us that this information Influenced a computer simulation of the process.


"in a closed garage where 800 grams of charcoal are burned, CO concentrations of between 750 and 1100 ppm are to be expected."


If we just go slap bang in the middle of those two readings, we can expect 925 ppm in the garage in around 2 hours.


Now, this doesn't sound too promising, maybe carbon monoxide death isn't worth trying?


Don't lose hope just yet! I will explain in the rest of this essay why this isn't as bad as it seems!


I would like to start by giving some visual references, so you can get some ideas of what this amount of charcoal may look like.




3)How much charcoal is enough?


So, as I said above, I would like to give you some idea of how much charcoal 800 grams really is.


As I said in my last post, I have already attempted to take my life using this method.

In that post I explained that I used the charcoal from 4 bar-be-quick instant BBQ's to go through with my plan.


Each of those BBQ's had 500 grams of Charcoal in them, giving a total of 2,000 grams of charcoal.

I explained in my post from yesterday, I managed to put all 4 grills into a metal popcorn bucket from Odeon, the local cinema.

Here are some pics so that you can visualise the size:










So, as you can see, 2,000 grams of charcoal isn't as much as you might think.


So, knowing this, I have attempted to roughly work out what 2,000 grams of charcoal would produce in the 19 cubic metre space.



If we use 925 ppm (in between 750 and 1100) and round the 800 grams up to 1,000:

2,000 grams of charcoal would be equal to 1,850 ppm.

This means that you would die in less than two hours whilst breathing the air in this space.


So, if you have the money and room, you should be able to buy more than 4 charcoal grills and up the ppm rather easily.


8 charcoal BBQ's at 500 grams each would put you up to 3,700 ppm, meaning you would die within half an hour.


(Also, just For reference, bar be quick in sainsburys is £2.50 and looking on Amazon they're around £5)




Now, it may appear that I am done. However, this leads me to the question of where on earth should I light my charcoal to achieve maximum effect.

I will be answering this question now.



4)How much space do I need.


So, in my last post, I explained that I attempted to end my life by putting smouldering charcoal IN MY CAR.


So, assuming that everyone has a car, or access to a similar sized unventilated place, id imagine you'd would probably find it preferable to attempt this method this way (in a smaller space), rather than using a living room or garage.




So, The average car passenger compartment is 105 cubic feet.



Here comes the absolutely insanely good news….. 105 cubic feet is equal to 2.97327 cubic metres!!! (Round that up to 3)


This means that a car, or similar sized space is almost FIVE TIMES SMALLER than the space tested in the experiment I am referencing!




5)I GUESS THE MOST IMPORTANT PART, FULL CALCULATIONS.


So, now, all that's left to do is the workings out.


IMPORTANT NOTICE, SCROLL DOWN TO THE BOTTOM OF THIS SECTION IF YOU WANT TO AVOID RAMBLING EQUATIONS.


So, if I've done my calculations correctly. (Bear with me this is where I find it a little complicated)


60X2 = 120 (120 mins)


3000ppm/ 3 = 1000 ppm

120 (mins)/ 3 = 40

19/3 = 6.33333 (6.33)



6.33 divided by itself = 1

40/6.33 = 6.319 (6.32)

1000/6.33 = 157.977 (157.98)




This may look like a whole lot of nonsense, but these calculations mean that it takes 6.32 minutes to fill 1 cubic metre with 157.977ppm


This means that the average car (3 cubic metres) takes takes 19 mins to fill with 473.931 if you use 800 grams of charcoal:



6.32X3 = 18.96 (essentially 19 mins)

157.977X3 = 473.931ppm




I know that there is a tapering point for CO with burning charcoal (as in, there is a point the CO won't go any higher), but if the findings from these calculations have a direct correlation with each-other, it should take


1000 grams of charcoal, 7.9 minutes to fill 1 cubic metre with 197.4762 (197.476ppm)



So, 4 charcoal BBQ's weighing 500 grams each (2000 grams), would take 15.8 minutes to fill 1 cubic metre with 394.9542ppm



(….. Reading this i'm starting to see why my attempt failed).



SO, This has been going on long enough, I do apologise for all of the equations.


The actual helpful sum ends up being that it takes:




2000 grams of charcoal, 47.4 minutes to fill the average 3 cubic metre interior of a car with 1,184.8626ppm.


Meaning, you'd need to wait 94.8 mins (1.58 hours) for your car to reach 2,369.7252ppm.



This means you'd probably want to (need to) wait 3.16 hours (and that's not 3 hours and 16 mins) to reach 4,739.4504 ppm.




6)CONCLUSION



To some, this may seem like good news, to some, it may seem like bad news.

However, what these equations do is leave it all down to an individuals personal preference (that is, if they want to go through within the charcoal CO method).


For example, you know that you will die in under 2 hours if you get in your car and it's at 1,600ppm, which is after roughly leaving the charcoal burn in your car for about an hour.

But, as we know, if you get in at this level the CO levels will still be climbing. This means that it'll almost certainly be MUCH less than 2 hours…. But you will still probably not have a massively pleasant time. (nausea and headaches)


Whereas, another individual may prefer to get in the car a little later, knowing that they will die within 30 minutes of entering their car, if they enter at around the 2 and a half hour mark at 2,400ppm (and yet again, this is whilst the concentration should still be rising).


Either way, it looks as though this method will be rather time consuming either way. I would recommend making sure you have at least 5-6 hours to go through with this plan.


Also, I think it's worth saying that, Sadly, I have to admit, if you wanted to reach the EXTREMELY lethal dose of 12,000ppm (at which you'd take 1 or two breaths, pass out and die within a few minutes), you'd either have to buy a whopping 24 packs of 500 grams charcoal and wait for nearly 2 hours.

Or:

you'd probably need somewhere along the lines of 12 packs, and wait nearly 4 hours before getting in.






7)FINAL CONCLUSION


Anyway. As always, I would like to thank you for reading this post!

I hope that you find the information held forthwith helpful (and if you spot any mistakes, or if you're a real scientist please don't hesitate to point them out/ call me out on it)


As I've said before, this is still my method of choice and for anyone else who is considering using this method, I am so ecstatically happy that you will now have the resources that I didn't at the stage of my first attempt.

Thank you very much!


I wish you all well.

Feel free to comment or message me and feel free to ask any questions you have!

Knion.

 

[Idontrecognizemyself]

LOVE this post!! This was so informative and helpful, and you are such an engaging writer. This was a pleasure to read thru. Has been my method of choice as well for many years. Wishing you all the best

 

[knion]

LOVE this post!! This was so informative and helpful, and you are such an engaging writer. This was a pleasure to read thru. Has been my method of choice as well for many years. Wishing you all the best

Thank you so much!

I really appreciate comments and feedback!
I'm glad you found it informative and that you think I'm an engaging writer!

I hope you are at peace in life, and if you are not that you find some way to be at peace in either life, or death.

 

[knion]

Hey!



FIRSTLY I WANT TO SAY THAT I HAVE MADE A GRAVE MISTAKE IN MY ORIGINAL POST.

I WILL KEEP IT POSTED AS A LOT OF THE INFORMATION (such as pictures and the weights of carbon) MAY STILL BE USEFUL.



HOWEVER, MY CALCULATIONS OF THE SPACE WITHIN A CAR AND THE TIME IT WOULD TAKE TO FILL WAS WRONG.



I HAVE NOW FIXED THIS MISTAKE IN THIS COMMENT/ POST.



THESE CALCULATIONS ARE NOT ONLY MORE ACCURATE BECAUSE I DID NOT MAKE A STUPID MISTAKE, BUT THEY ARE ALSO MUCH MUCH MORE IN DEPTH.



I would like to thank Bedrock48 for their comment. Without it I wouldn't have found my mistake.



I also realise that I am posting a lot on this website, so don't worry, I will take a while off after this! Haha.





IF YOU WISH TO SEE THE HELPFUL STUFF, RATHER THAN A WHOLE LOT OF WORKINGS OUT, PLEASE SCROLL STRAIGHT TO THE BOTTOM.





Ok, so it took a little while, but I found some info on this.

Here is a picture that outlines the properties of different types of charcoal (incase anyone was interested)







I also found a study about the concentration of CO in a certain area. And this study appears to have used Binchotan as it's charcoal of choice.



"if the concentration of carbon in the briquettes is 85%, the lethal concentration of CO is 10 000 ppm and the volume of an apartment is 100 m3, then burning 629 g of charcoal briquettes could produce a potentially toxic atmosphere." - (https://www.mja.com.au/journal/2012...nduced-death-and-toxicity-charcoal-briquettes).



Sadly this study didn't focus on the time it took to produce this effect.

HOWEVER, it does tell us that only 629 g of Binchotan charcoal briquettes will achieve 10000ppm at some point, a particularly lethal concentration.





To help understand what this means and even try to figure out the timings on this, I also found another study.



This study measured the speed at which 50-100g of charcoal produced Carbon monoxide.



these were the results:









(https://www.jniosh.johas.go.jp/en/indu_hel/doc/IH_49_3_393.pdf)



I'm entirely new to the "±" symbol, but apparently it is "the confidence interval or error in a measurement"



So, for example, sample A, where it says 185 ± 31, it actually just means *roughly 185*. This is because, if I'm right, the outcome is within the realm of 185 but potentially plus OR minus 31.







It's at this point I'd like to say that I'm sorry. This reply is extremely lengthy.

I at least hope that they are genuinely useful.







Anyways.

To continue, it looks as though (If I understand this correctly), the 'best' binchotan (sample A) which i'd imagine is 85% carbon at least, releases roughly 185 ml of CO per minute.



To figure out how long it would take to get to a high enough ppm using this 85% carbon, we'll need to do some equations.



By the way, for anyone confused, as I was for a long while, PPM is an abbreviation for "parts per million" and it also can be expressed as milligrams per liter (mg/L)

PPM is calculated by dividing the mass of the solute by the mass of the solution, then multiplying by 1,000,000





So.



Let's use the example of the the room from earlier (100 m3). This room as litres would be 100,000 litres



1,000 ml is a litre.



185 ml is 0.185 litres.



So, the mass of the 'solution' (the air in the room), is 100,000 litres.



(1 minute of carbon burning) 0.185(ml) X 60 (mins) = 11.1 (litres)



11.1 (litres) / 100,000 (litres) = 0.000111 (litres)



0.000111 (litres) X 1,000,000 = 111 ppm



So it would take an hour for 50-100g (let's say 75g) of 85% Carbon to get to 111pm in a 100m3 room.







I mean, this obviously isn't going to be enough to satisfyingly end your life. So, let's use the amount of charcoal from earlier.



75g/75 = 1g



111pm / 75 = 1.48



1.48 X 629 = 930.92



So, 629 grams of 85% charcoal in a 100m3 room would take an hour to get to 930.92 ppm of CO.

So this means, in the initial test that I talked about, they probably measured that it got to 10,000 ppm after around, well, 10 hours

(which would obviously still make sense and be alarming in the context of the research, because it is surrounding cooking inside buildings such as restaurants, which are open for extended periods of time)





Anyway.



To finally answer your (Bedrock48) question.

If we assume that binchotan is 85% charcoal, and the BBQ charcoal briquettes are roughly 75% you would be correct in saying that the effect would not only create less smoke (as that is something binchotan does), but it would also cause death much more quickly, (or you would at least need more of the briquettes to achieve the same effect, but not A LOT more as far as I can tell).





If we want prove this, all we really need to do is as follows:



If it takes 629 grams of 85% charcoal an hour to fill a 100m3 room with 930.92 ppm, then:



629g / 85 = 7.4 g



85g - 75g = 10g



85g + 10g = 95



7.4 X 95 = 703



It would take 704 grams of 75% carbon an hour to fill a 100m3 room with 930.92 ppm.



So 85% charcoal only needs 629 grams to beat 75% charcoal's 704 grams to achieve the same goal in the same time.







CHARCOAL CARBON MONOXIDE IN A SMALL SPACE.



So, as I said at the beginning of this post/ reply, I made a massive mistake in the original post.



So, this is where I would like to make up my mistake by talking about the time it would take to die in the same space as, say, a car, through this method.



(Just an FYI, it gets even MORE tricky from this point.)





So, 930.92 ppm is 930.92 g/ litre.



A single m3 is 1000 litres and 100m3 holds 100,000 litres.



So If it takes one hour to reach 930.92 g/litre in a 100,000 litre room, Then, in a room only 3,000 litres big:



100/3 = 33.43333333333333



33.43333333333333 X 1,000 = 33,433.33333



33,433.33333 X 930.92 = 31,123,758.66666667



An hour would've been enough time to reach 31,123,758.666666667ppm (which obviously doesn't make sense).



So this means, if 60 minutes would have had to have passed to achieve the 31,123,758.7ppm, we would achieve 1ppm in 0.000001927787728 minutes. This is 1.927788e seconds



SO, to achieve the lethal dose of 10,000ppm that we want in our (on average) 3 cubic metre car, we would want to wait:



1ppm X 10,000 = 10,000 ppm



1.927788e X 10,000 = 19,277.88



This is equal to 5.3547222222222 hours!

(And this is the case with 705 grams of 75% charcoal, and 629 grams of 85% charcoal, more charcoal would achieve affects more quickly)









ANYWAYS, THE REAL IMPORTANT, MINI VERSION OF THIS STUFF IS BELOW:



If you saw this post/ reply and thought, wow, that's way too much to read. Here is what I have found.

1,600 ppm (0.16%), (1.6‰)

Headache, increased heart rate, dizziness, and nausea within 20 min; death in less than 2 hour

3,200 ppm (0.32%), (3.2‰)

Headache, dizziness and nausea in five to ten minutes. Death within 30 mins.

6,400 ppm (0.64%), (6.4‰)

Headache and dizziness in one to two minutes. Convulsions, respiratory arrest, and death in less than 20 minutes

12,800 ppm (1.28%), (12.8‰)

Unconsciousness after 2–3 breaths. Death in less than three minutes

It would take 629 grams of 85% charcoal (binchotan) one hour to reach 930.92 ppm in a room 100 cubic metres big.

It would take 704 grams of 75% charcoal to have the same effect.



AND, most importantly, it would take just over 5 hours for 629 grams of 85% charcoal, OR 704 grams of 75% charcoal to reach 10,000ppm in a car with an interior that measures 3 cubic.







Anyways.



Yet again, I profusely apologise for the mistake I made in my last post. I am extremely sorry about that.



I hope that this message will be helpful and easy to read for all of you who wish to CTB by carbon monoxide poisoning via Charcoal.



Thank you all so much,



Knion.